Summary

Fittings such as elbows, tees and valves represent a significant component of the pressure loss in most pipe systems. This article details the calculation of pressure losses through pipe fittings and some minor equipment using the equivalent length method. The strength of the equivalent length method is that it is very simple to calculate. The weakness of the equivalent length method is that it is not as accurate as other methods unless very detailed tabulated data is available.

Definitions

DD:Internal diameter of pipe
(L/D)eq(L/D)_{eq}:Equivalent length of pipe
R/DR/D:Ratio of elbow radius to pipe diameter

Introduction

The equivalent length method (L/D ratio) allows the user to describe the pressure drop through a fitting as a length of pipe. In theory the pressure drop through the fitting is equivalent to the pressure lost through a certain length of piping at that corresponding flow rate.

The most accurate way to use this method is when tabulated data is available for fittings at the given size, roughness and Reynolds Number for which the pressure drop is unknown. When using an equivalent length that was determined from a fitting of a different size the method relies on the assumption that as pipe size changes the fitting size retains the same relative proportions. This is rarely the case however, and as such some error is introduced in the pressure drop that results. Similarly the roughness and Reynolds Number are likely to be different from the conditions under which the fitting was characterised and error will be introduced.

Typically as the fittings size increase the flow coefficient (L/D ratio) decreases, thus at pipe sizes larger than those at which the fittings equivalent length was determined the pressure drop will be over-estimated. At smaller pipe sizes than those at which the equivalent length was estimated the pressure drop will be under-estimated.

The advantage of the equivalent length method is that it is very simple to calculate. All pipe runs and fittings can be summed up to make one total length, and the pressure loss calculated from this length.

There are several alternative methods for calculating pressure loss from fittings, such as:

For a discussion of which method is most appropriate see this summary of methods for estimating pressure loss from fittings.

Values for the Equivalent Length of Pipe for Various Fittings

Typical values for the equivalent length of pipe for various fittings are shown in the table below.

After summing these equivalent lengths as appropriate for your hydraulic system, you may simply calculate the pressure drop for the resulting length of pipe.

CategoryFittingTypes(L/D)eq(L/D)_{eq}
Elbow90° Curved, ThreadedStandard Radius (R/D = 1)30
Elbow90° Curved, ThreadedLong Radius (R/D = 1.5)16
Elbow90° Curved, Flanged/WeldedStandard Radius (R/D = 1)20
Elbow90° Curved, Flanged/WeldedLong Radius (R/D = 2)17
Elbow90° Curved, Flanged/WeldedLong Radius (R/D = 4)14
Elbow90° Curved, Flanged/WeldedLong Radius (R/D = 6)12
Elbow90° Mitered1 weld (90°)60
Elbow90° Mitered2 welds (45°)15
Elbow90° Mitered3 welds (30°)8
Elbow45° Curved, ThreadedStandard Radius (R/D = 1)16
Elbow45° Curved, ThreadedLong Radius (R/D = 1.5)
Elbow45° Mitered1 weld 45°15
Elbow45° Mitered2 welds 22.5°6
Elbow180° BendThreaded, close-return (R/D = 1)50
Elbow180° BendFlanged (R/D = 1)
Elbow180° BendAll types (R/D = 1.5)
TeeThrough-branch as an ElbowThreaded (r/D = 1)60
TeeThrough-branch as an ElbowThreaded (r/D = 1.5)
TeeThrough-branch as an ElbowFlanged (r/D = 1)20
TeeThrough-branch as an ElbowStub-in branch
TeeRun-throughThreaded (r/D = 1)20
TeeRun-throughFlanged (r/D = 1)
TeeRun-throughStub-in branch
ValveAngle valve45°, full line size, β=1\beta = 155
ValveAngle valve90° full line size, β=1\beta = 1150
ValveGlobe valveStandard, β=1\beta = 1340
ValvePlug valveBranch flow90
ValvePlug valveStraight through18
ValvePlug valveThree-way (flow through)30
ValveGate valveStandard, β=1\beta = 18
ValveBall valveStandard, β=1\beta = 13
ValveDiaphragmDam type
ValveSwing check valveVmin⁡=35[ρ(lbm/ft3)]−1/2V_{\min} = 35[\rho (\text{lb}_{\text{m}}/\text{ft}^{3})]^{-1/2}100
ValveLift check valveVmin⁡=40[ρ(lbm/ft3)]−1/2V_{\min} = 40[\rho (\text{lb}_{\text{m}}/\text{ft}^{3})]^{-1/2}600
TeeHose CouplingSimple, Full Bore5

Example Calculation of Pressure Loss using Equivalent Lengths

This example demonstrates how to use the equivalent length method to calculate the pressure loss through simple pipe and fitting arrangement. The example uses water in system of standard weight carbon steel pipe. Note that for this example we consider a flat system, with no elevation changes.

Equivalent Length Example

System details

ItemValue
Pipe SizeDN100 (4")
Pipe Diameter102.3 mm
Pipe Length50 m
Fittings3 × 90° long radius (R/D = 2) elbows
Fluid Velocity3 m/s
Fluid Density1000 kg/m^{3}
Friction Factor0.018

Calculation

Using the table of fittings and equivalent lengths above we find that the equivalent length for the 90° elbow is 17 pipe diameters.

Leq=17×102.3 mm=1.739 m L_{eq} = 17 \times 102.3 \text{ mm} = 1.739 \text{ m}

Taking the pipe length and number of elbows we calculated the equivalent length of the pipe work for pressure loss purposes.

Leq=50+3×1.739=55.217 m L_{eq} = 50 + 3 \times 1.739 = 55.217 \text{ m}

Using the equation for pressure loss in pipe:

Δp=fLDρV22Δp=0.01855.217102.3/10001000×322Δp=43.7 kPa \begin{aligned} \Delta p &= f \frac{L}{D} \frac{\rho V^2}{2} \\ \Delta p &= 0.018 \frac{55.217}{102.3/1000} \frac{1000 \times 3^2}{2} \\ \Delta p &= 43.7 \text{ kPa} \end{aligned}